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lab05_en:inverting_op-amp_basics_amplification [2026/05/07 12:31] – mexleadminlab05_en:inverting_op-amp_basics_amplification [2026/05/07 12:45] (current) – mexleadmin
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-Calculate the necessary value for $R_{\rm 2}$, so that the output $U_{\rm OUT}$ is +1.5 V.+Calculate the necessary value for $R_{\rm 2}$, so that the output $U_{\rm OUT}$ is +1.5 V.\\
 Use the supply voltage of the operational amplifier for $U_{\rm IN}$. Use the supply voltage of the operational amplifier for $U_{\rm IN}$.
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 == Analysis of inverting input currents == == Analysis of inverting input currents ==
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 {{drawio>lab05:Fig-30_inverting_op-amp_inv_input.svg}} {{drawio>lab05:Fig-30_inverting_op-amp_inv_input.svg}}
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-$U_{\rm DD}{\rm~=10~V},~U_{\rm SS}{\rm~=-10~V},~R_{\rm 1}{\rm~=100~k\Omega}$+$U_{\rm DD}{\rm~=10~V},~U_{\rm SS}{\rm~=-10~V},~R_{\rm 1}{\rm~=100~k\Omega}$\\
 Use the values from <imgref Fig-20_inverting_op-amp> for $U_{\rm IN},~U_{\rm OUT},~R_{\rm 2}$. Use the values from <imgref Fig-20_inverting_op-amp> for $U_{\rm IN},~U_{\rm OUT},~R_{\rm 2}$.
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 $I_{\rm N12}{\rm~=}$ $I_{\rm N12}{\rm~=}$
 == Analysis of inverting input voltages == == Analysis of inverting input voltages ==
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-$U_{\rm DD}{\rm~=10~V},~U_{\rm SS}{\rm~=-10~V},~R_{\rm 1}{\rm~=100~k\Omega}$\\ \\+$U_{\rm DD}{\rm~=10~V},~U_{\rm SS}{\rm~=-10~V},~R_{\rm 1}{\rm~=100~k\Omega}$\\
 Use the values from <imgref Fig-20_inverting_op-amp> for $U_{\rm IN},~U_{\rm OUT},~R_{\rm 2}$. Use the values from <imgref Fig-20_inverting_op-amp> for $U_{\rm IN},~U_{\rm OUT},~R_{\rm 2}$.
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-$U_{\rm OUT}{\rm~=}$+$U_{\rm IN}{\rm~=}$
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