Differences

This shows you the differences between two versions of the page.

--- lab_electrical_engineering:1_resistors:mesh-set [2026/03/10 03:22] – created mexleadmin
+++ lab_electrical_engineering:1_resistors:mesh-set [2026/03/16 02:04] (current) – mexleadmin
@@ Line 1: / Line 1: @@
-==== Mesh set ====
+====== Loop law ======
-\\
+**Kirchhoff's voltage law:** In every closed loop of an electrical network, the sum of all voltages is zero.
-**In every closed circuit and every mesh of the network, the sum of all voltages is zero!** \\
-Set the voltage on the power supply to $12~\rm V$ and measure this voltage precisely using a multimeter. Set up the measuring circuit shown in <imgref Fig-2_Mesh-set_V1>.
-{{drawio>Fig-1_Mesh-set_V1.svg}}\\
+Set the voltage on the power supply to $12 ~{\rm V}$ and measure this voltage accurately using a multimeter. Build the measurement circuit shown in <imgref Fig-2_loop-law_V1>.
-<imgcaption Fig-2_Mesh-set_V1 | Mesh-set> </imgcaption>
-Add the voltage arrows and measure $U$, $U_{\rm 1}$ und $U_{\rm 2}$:
+{{drawio>lab_electrical_engineering:1_resistors:Fig-1_Mesh-set_V1.svg}}
+<imgcaption Fig-2_loop-law_V1 | Verification of Kirchhoff's voltage law> </imgcaption>
-{{drawio>Table-1_Mesh-set_V1.svg}}\\
+Add the voltage arrows and measure $U$, $U_{\rm 1}$ and $U_{\rm 2}$.
-<tabcaption Table-4_mesh-set_V1 | Mesh set voltage mesurement> </tabcaption>
-What is the mesh set here? <wrap onlyprint>\\
+{{drawio>lab_electrical_engineering:1_resistors:Table-1_Mesh-set_V1.svg}}
-\\
+<tabcaption Table-4_loop-law_V1 | Voltage measurement for Kirchhoff's voltage law> </tabcaption>
-\\
-\\
-</wrap>
-Check the formula with the measured values: <wrap onlyprint>\\
+What is the loop equation here?
-\\
+\\ \\ \\ \\  \\ \\ \\ \\
-\\
-\\
-</wrap>
-The resistors $R_{\rm 1}$ and $R_{\rm 2}$ connected in series form a voltage divider. What is the ratio between the voltages $U_{\rm 1}$ and $R_{\rm 2}$?
+Verify the equation using the measured values.
+ \\ \\ \\ \\   \\ \\ \\ \\
-$$ \frac{U_1}{U_2} = $$
+The resistors $R_{\rm 1}$ and $R_{\rm 2}$ connected in series form a voltage divider. In what ratio are the voltages $U_{\rm 1}$ and $U_{\rm 2}$?
-==== Set of nodes ====
+$\frac{U_{\rm 1}}{U_{\rm 2}} =$ \\ \\
-\\
-**At each junction point, the sum of all incoming and outgoing currents is equal to zero!** \\
-Set the voltage on the power supply to $12~\rm V$ and measure the voltage accurately with a multimeter. In the first step, set up the measuring circuit shown in <imgref Fig-3-Node-set-1_V1>:
-{{drawio>Fig-3_V1-Node-Set-1.svg}} <imgcaption Fig-3-Node-set-1_V1 | Node-set circuit 1> </imgcaption>
+===== Node law ======
-Draw the arrows for the directions of currents $I_{\rm 1}$ and $I_{\rm 2}$ in <imgref Fig-4-Node-set-2_V1>. The DC current measurement range must be set on both multimeter using the rotary switch. Then measure currents $I_{\rm 1}$ and $I_{\rm 2}$ and enter the measured values in <tabref Table-5_Node-set_V1>.
+**Kirchhoff's current law:** At every node, the sum of all currents flowing into and out of the node is zero.
-{{drawio>Fig-4_V1-Node-Set-2.svg}}
+Set the voltage on the power supply to $12 ~{\rm V}$ and measure the voltage accurately using a multimeter. As a first step, build the measurement circuit shown in <imgref Fig-3_node-law-branch-currents_V1>.
-<imgcaption Fig-4-Node-set-2_V1 | Node-set circuit 2> </imgcaption>
-What is the relationship between currents $I_{\rm 1}$ and $I_{\rm 2}$?
+{{drawio>lab_electrical_engineering:1_resistors:Fig-3_V1-Node-Set-1.svg}}
+<imgcaption Fig-3_node-law-branch-currents_V1 | Branch currents for verification of Kirchhoff's current law> </imgcaption>
-$$ \frac{I_1}{I_2} = $$
+Add the arrows indicating the directions of currents $I_{\rm 1}$ and $I_{\rm 2}$. On both multimeters, set the DC current range and the polarity before switching on. Then measure currents $I_{\rm 1}$ and $I_{\rm 2}$ and enter the measured values in the table.
-Switch the power supply back on and measure the current $I$. Enter its value in <tabref Table-5_Node-set_V1>.
+{{drawio>lab_electrical_engineering:1_resistors:Fig-4_V1-Node-Set-2.svg}}
+<imgcaption Fig-4_node-law-total-current_V1 | Total current and node $K$> </imgcaption>
-{{drawio>Table-5_Node-set_V1.svg}}\\
+In what ratio are currents $I_{\rm 1}$ and $I_{\rm 2}$?
-<tabcaption Table-5_Node-set_V1 | Node set current mesurement> </tabcaption>
-Determine the node set for node K and check its validity.\\
+$\frac{I_{\rm 1}}{I_{\rm 2}} =$ \\ \\
-\\
-Using the measured values for resistors $R_{\rm 1}$, $R_{\rm 2}$, and $R_{\rm 3}$, calculate the total resistance $R_{\rm KP}$:\\
+Switch the power supply on again and measure the current $I$. Enter its value in the table.
-\\
-Using the calculated value $R_{\rm KP}$, check the measured value of the total current:\\
+{{drawio>lab_electrical_engineering:1_resistors:Table-5_Node-set_V1.svg}}
-$$ I=\frac{U}{R_{KP}} = $$
+<tabcaption Table-5_node-law_V1 | Current measurement for Kirchhoff's current law> </tabcaption>
+Determine the node equation for node $K$ and verify its validity.
+\\ \\ \\ \\  \\ \\
+Using the measured values of resistors $R_{\rm 1}$, $R_{\rm 2}$ and $R_{\rm 3}$, calculate the total resistance $R_{\rm KP}$.
+\\ \\ \\ \\ \\ \\ \\ \\
+Using the calculated value of $R_{\rm KP}$, verify the measured value of the total current:
+$I = \frac{U}{R_{\rm KP}} =$ \\ \\ \\ \\ \\ \\ \\ \\