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lab_electrical_engineering:1_resistors:mesh-set [2026/03/15 20:14] – [Mesh set] mexleadminlab_electrical_engineering:1_resistors:mesh-set [2026/03/16 02:04] (current) mexleadmin
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-==== Mesh set ====+====== Loop law ======
  
-\\ +**Kirchhoff's voltage law:** In every closed loop of an electrical network, the sum of all voltages is zero.
-**In every closed circuit and every mesh of the network, the sum of all voltages is zero!** \\ +
-Set the voltage on the power supply to $12~\rm V$ and measure this voltage precisely using a multimeter. Set up the measuring circuit shown in <imgref Fig-2_Mesh-set_V1>.+
  
-{{drawio>lab_electrical_engineering:1_resistors:Fig-1_Mesh-set_V1.svg}}\\ +Set the voltage on the power supply to $12 ~{\rm V}$ and measure this voltage accurately using a multimeterBuild the measurement circuit shown in <imgref Fig-2_loop-law_V1>.
-<imgcaption Fig-2_Mesh-set_V1 | Mesh-set> </imgcaption>+
  
-Add the voltage arrows and measure $U$, $U_{\rm 1}$ und $U_{\rm 2}$:+{{drawio>lab_electrical_engineering:1_resistors:Fig-1_Mesh-set_V1.svg}} 
 +<imgcaption Fig-2_loop-law_V1 | Verification of Kirchhoff's voltage law> </imgcaption>
  
-{{drawio>lab_electrical_engineering:1_resistors:Table-1_Mesh-set_V1.svg}}\+Add the voltage arrows and measure $U$, $U_{\rm 1}$ and $U_{\rm 2}$.
-<tabcaption Table-4_mesh-set_V1 | Mesh set voltage measurement> </tabcaption>+
  
-What is the mesh set here? <wrap onlyprint>\\ +{{drawio>lab_electrical_engineering:1_resistors:Table-1_Mesh-set_V1.svg}} 
-\\ +<tabcaption Table-4_loop-law_V1 | Voltage measurement for Kirchhoff's voltage law> </tabcaption>
-\\ +
-\\ +
-</wrap>+
  
-Check the formula with the measured values: <wrap onlyprint>\\ +What is the loop equation here? 
-\\ +\\ \\ \\ \\  \\ \\ \\ \\ 
-\\ +
-\\ +
-</wrap>+
  
-The resistors $R_{\rm 1}$ and $R_{\rm 2}$ connected in series form a voltage divider. What is the ratio between the voltages $U_{\rm 1}$ and $R_{\rm 2}$?+Verify the equation using the measured values. 
 + \\ \\ \\ \\   \\ \\ \\ \\ 
  
-$\frac{U_1}{U_2$$+The resistors $R_{\rm 1}$ and $R_{\rm 2}$ connected in series form a voltage divider. In what ratio are the voltages $U_{\rm 1}$ and $U_{\rm 2}$?
  
-==== Set of nodes ====+$\frac{U_{\rm 1}}{U_{\rm 2}} =$ \\ \\ 
  
-\\ 
-**At each junction point, the sum of all incoming and outgoing currents is equal to zero!** \\ 
-Set the voltage on the power supply to $12~\rm V$ and measure the voltage accurately with a multimeter. In the first step, set up the measuring circuit shown in <imgref Fig-3-Node-set-1_V1>: 
  
-{{drawio>lab_electrical_engineering:1_resistors:Fig-3_V1-Node-Set-1.svg}} <imgcaption Fig-3-Node-set-1_V1 | Node-set circuit 1> </imgcaption>+===== Node law ======
  
-Draw the arrows for the directions of currents $I_{\rm 1}$ and $I_{\rm 2}$ in <imgref Fig-4-Node-set-2_V1>. The DC current measurement range must be set on both multimeter using the rotary switch. Then measure currents $I_{\rm 1}$ and $I_{\rm 2}$ and enter the measured values in <tabref Table-5_Node-set_V1>.+**Kirchhoff's current law:** At every node, the sum of all currents flowing into and out of the node is zero.
  
-{{drawio>lab_electrical_engineering:1_resistors:Fig-4_V1-Node-Set-2.svg}}  +Set the voltage on the power supply to $12 ~{\rm V}$ and measure the voltage accurately using a multimeterAs a first step, build the measurement circuit shown in <imgref Fig-3_node-law-branch-currents_V1>.
-<imgcaption Fig-4-Node-set-2_V1 | Node-set circuit 2> </imgcaption>+
  
-What is the relationship between currents $I_{\rm 1}$ and $I_{\rm 2}$?+{{drawio>lab_electrical_engineering:1_resistors:Fig-3_V1-Node-Set-1.svg}} 
 +<imgcaption Fig-3_node-law-branch-currents_V1 | Branch currents for verification of Kirchhoff's current law> </imgcaption>
  
-$\frac{I_1}{I_2$$+Add the arrows indicating the directions of currents $I_{\rm 1}$ and $I_{\rm 2}$. On both multimeters, set the DC current range and the polarity before switching on. Then measure currents $I_{\rm 1}$ and $I_{\rm 2}and enter the measured values in the table.
  
-Switch the power supply back on and measure the current $I$Enter its value in <tabref Table-5_Node-set_V1>.+{{drawio>lab_electrical_engineering:1_resistors:Fig-4_V1-Node-Set-2.svg}} 
 +<imgcaption Fig-4_node-law-total-current_V1 | Total current and node $K$> </imgcaption>
  
-{{drawio>lab_electrical_engineering:1_resistors:Table-5_Node-set_V1.svg}}\+In what ratio are currents $I_{\rm 1}$ and $I_{\rm 2}$?
-<tabcaption Table-5_Node-set_V1 | Node set current mesurement> </tabcaption>+
  
-Determine the node set for node K and check its validity.\\ +$\frac{I_{\rm 1}}{I_{\rm 2}} =$ \\ \\  
-\\ + 
-Using the measured values for resistors $R_{\rm 1}$, $R_{\rm 2}$and $R_{\rm 3}$, calculate the total resistance $R_{\rm KP}$:\\ +Switch the power supply on again and measure the current $I$. Enter its value in the table. 
-\\ + 
-Using the calculated value $R_{\rm KP}$, check the measured value of the total current:\\ +{{drawio>lab_electrical_engineering:1_resistors:Table-5_Node-set_V1.svg}} 
-$$ I=\frac{U}{R_{KP}} = $$+<tabcaption Table-5_node-law_V1 | Current measurement for Kirchhoff's current law> </tabcaption> 
 + 
 +Determine the node equation for node $Kand verify its validity. 
 +\\ \\ \\ \\  \\ \\  
 + 
 +Using the measured values of resistors $R_{\rm 1}$, $R_{\rm 2}$ and $R_{\rm 3}$, calculate the total resistance $R_{\rm KP}$
 +\\ \\ \\ \\ \\ \\ \\ \\ 
 + 
 + 
 +Using the calculated value of $R_{\rm KP}$, verify the measured value of the total current: 
 + 
 +$I = \frac{U}{R_{\rm KP}} =$ \\ \\ \\ \\ \\ \\ \\ \\