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| Both sides previous revision Previous revision Next revision | Previous revision | ||
| lab_electrical_engineering:1_resistors:mesh-set [2026/03/16 00:01] – mexleadmin | lab_electrical_engineering:1_resistors:mesh-set [2026/03/16 02:04] (current) – mexleadmin | ||
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| What is the loop equation here? | What is the loop equation here? | ||
| - | <wrap onlyprint> | + | \\ \\ \\ \\ \\ \\ \\ \\ |
| Verify the equation using the measured values. | Verify the equation using the measured values. | ||
| - | <wrap onlyprint> | + | \\ \\ \\ \\ \\ \\ \\ \\ |
| The resistors $R_{\rm 1}$ and $R_{\rm 2}$ connected in series form a voltage divider. In what ratio are the voltages $U_{\rm 1}$ and $U_{\rm 2}$? | The resistors $R_{\rm 1}$ and $R_{\rm 2}$ connected in series form a voltage divider. In what ratio are the voltages $U_{\rm 1}$ and $U_{\rm 2}$? | ||
| - | $\frac{U_{\rm 1}}{U_{\rm 2}} =$ <wrap onlyprint> | + | $\frac{U_{\rm 1}}{U_{\rm 2}} =$ \\ \\ |
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| In what ratio are currents $I_{\rm 1}$ and $I_{\rm 2}$? | In what ratio are currents $I_{\rm 1}$ and $I_{\rm 2}$? | ||
| - | $\frac{I_{\rm 1}}{I_{\rm 2}} =$ <wrap onlyprint> | + | $\frac{I_{\rm 1}}{I_{\rm 2}} =$ \\ \\ |
| Switch the power supply on again and measure the current $I$. Enter its value in the table. | Switch the power supply on again and measure the current $I$. Enter its value in the table. | ||
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| Determine the node equation for node $K$ and verify its validity. | Determine the node equation for node $K$ and verify its validity. | ||
| - | <wrap onlyprint> | + | \\ \\ \\ \\ \\ \\ |
| Using the measured values of resistors $R_{\rm 1}$, $R_{\rm 2}$ and $R_{\rm 3}$, calculate the total resistance $R_{\rm KP}$. | Using the measured values of resistors $R_{\rm 1}$, $R_{\rm 2}$ and $R_{\rm 3}$, calculate the total resistance $R_{\rm KP}$. | ||
| - | <wrap onlyprint> | + | \\ \\ \\ \\ \\ \\ \\ \\ |
| Using the calculated value of $R_{\rm KP}$, verify the measured value of the total current: | Using the calculated value of $R_{\rm KP}$, verify the measured value of the total current: | ||
| - | $I = \frac{U}{R_{\rm KP}} =$ <wrap onlyprint> | + | $I = \frac{U}{R_{\rm KP}} =$ \\ \\ \\ \\ \\ \\ \\ \\ |